standards/52972: /bin/sh arithmetic not POSIX compliant
Wartan Hachaturow
wart at tepkom.ru
Mon Jun 23 03:10:23 PDT 2003
The following reply was made to PR standards/52972; it has been noted by GNATS.
From: Wartan Hachaturow <wart at tepkom.ru>
To: Dag-Erling Sm?rgrav <des at des.no>
Cc: freebsd-gnats-submit at freebsd.org
Subject: Re: standards/52972: /bin/sh arithmetic not POSIX compliant
Date: Mon, 23 Jun 2003 14:06:19 +0400
On Mon, Jun 23, 2003 at 08:32:55AM +0200, Dag-Erling Sm?rgrav wrote:
> Yes, it should be left as-is so the part of the code that evaluates
> arithmetic expressions knows what variable is involved. For instance,
> "$(($a+=1)) would expand to "$((1+=1))" before evaluation, which makes
> no sense, while "$((a+=1))" clearly says to increase a with 1.
Yes, the latter was the thing that I couldn't understand -- how may one
implement +=, if variables are not required in arithmetic evaluation.
But now, I've noticed the line I've missed while reading SUS:
"Arithmetic Precision and Operations
Integer variables and constants, including the values of operands and
option-arguments, used by the standard utilities listed in this volume
of IEEE Std 1003.1-2001 shall be implemented"
Question is closed :)
--
Regards, Wartan.
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