why does this simple counter fail?
editor at d3photography.com
Thu Mar 24 23:25:53 UTC 2011
Gary, you missed the put... fput($fp, $file); means you're dropping the filename INTO the storage file.
On Mar 24, 2011, at 6:00 PM, Gary Kline wrote:
> On Wed, Mar 23, 2011 at 07:11:15PM +0100, Fr?d?ric Perrin wrote:
>> Gary Kline <kline at thought.org> writes:
>>> Can any of you php hackers tell me why this simple self-hacked
>>> counter bomb?
>> As others said, what does 'this simple counter bomb' means?
>>> $fp = fopen($directory.$file, "r+");
>>> flock($fp, 1);
>> You want an exclusive lock (LOCK_EX, which is 2 is you use some ancient
>> PHP), not a shared lock.
>> When updating the file:
>> > fputs($fp, $count);
>> > fputs($fp, "\n");
>>> fputs($fp, $file);
>> Why do you feel the need to store the filename inside the file itself?
>> You don't seem to need it after.
> $file is passed from the calling php file. index.php is by-hand
> set to
> and so on.
> Because of my shoulder/typing woes, it was great that I got clued in
> above by Brad's thought that perhaos there were mis-matched "<?"
> and "?>" tags. A simply recursive grepping found out that it some
> places I had "<?" <cr> instead of "<?php"> <cr>. Adding the "php"
> fixed everything.
> Finally, you're right; this really, really is ancient php.
> Somthing i found pre-2004 and hacked until it worked. The
> counter is missings lots of features, but I'll fix that pretty
> thanks to everybody ,
>> Frédéric Perrin -- http://tar-jx.bz
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> Gary Kline kline at thought.org http://www.thought.org Public Service Unix
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