Problem with bash script
danielby at slightlystrange.org
Tue Jun 16 15:16:31 UTC 2009
On Tue, Jun 16, 2009 at 02:33:37PM +0000, Paul Schmehl wrote:
> --On Tuesday, June 16, 2009 08:09:09 -0500 Carmel NY
> <carmel_ny at hotmail.com> wrote:
> >I am attempting to write a simple Bash script that will find all the
> >'*.pem' files in a directory structure and move them to another
> >directory. It seems to work until I get to the copy part where it fails.
> >My scripting skills are not that good. Perhaps someone could tell me
> >what I am doing wrong.
> >This is the script:
> ># ! /usr/bin/env bash
> ># Save the field separator
> ># Set it to line breaks
> >for i in $(find ./ -name "*.pem" -print); do
> ># Get the basename
> >BN=$(basename $i)
> ># copy the file to another directory using the base name
> >cp $i /usr/home/tmp/$BN
> ># Reset the IFS variable
> When I write scripts, I test them on the commandline to see if they're
> doing what I think they're doing. I don't get the $(find ....)
It does exactly the same as `command -a rgs`, but all characters between
the parentheses are taken literally (in the backtick form, certain chars
have special meaning, but not in the $() form.)
> construction. You're invoking find from within a for loop to return a
> value. Use backticks.
> This works.
> for i in `find ./ -name "*.pem" -print`
It also works with the $() form, provided the target directory exists!
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