Problem with bash script

Daniel Bye danielby at slightlystrange.org
Tue Jun 16 15:16:31 UTC 2009


On Tue, Jun 16, 2009 at 02:33:37PM +0000, Paul Schmehl wrote:
> --On Tuesday, June 16, 2009 08:09:09 -0500 Carmel NY 
> <carmel_ny at hotmail.com> wrote:
> 
> >
> >I am attempting to write a simple Bash script that will find all the
> >'*.pem' files in a directory structure and move them to another
> >directory. It seems to work until I get to the copy part where it fails.
> >
> >My scripting skills are not that good. Perhaps someone could tell me
> >what I am doing wrong.
> >
> >This is the script:
> >
> ># ! /usr/bin/env bash
> >
> ># Save the field separator
> >oIFS=$IFS
> >
> ># Set it to line breaks
> >IFS=$'\n'
> >
> >for i in $(find ./ -name "*.pem" -print); do
> >
> ># Get the basename
> >BN=$(basename $i)
> >
> ># copy the file to another directory using the base name
> >cp $i /usr/home/tmp/$BN
> >
> >done
> >
> ># Reset the IFS variable
> >IFS=$oIFS
> >
> >exit
> >
> 
> When I write scripts, I test them on the commandline to see if they're 
> doing what I think they're doing.  I don't get the $(find ....) 

It does exactly the same as `command -a rgs`, but all characters between
the parentheses are taken literally (in the backtick form, certain chars
have special meaning, but not in the $() form.)

> construction.  You're invoking find from within a for loop to return a 
> value.  Use backticks.
> 
> This works.
> 
> for i in `find ./ -name "*.pem" -print`
> do
> foo
> bar
> done

It also works with the $() form, provided the target directory exists!

Dan

-- 
Daniel Bye
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