Problem with bash script
Paul Schmehl
pauls at utdallas.edu
Tue Jun 16 15:02:39 UTC 2009
--On Tuesday, June 16, 2009 08:09:09 -0500 Carmel NY <carmel_ny at hotmail.com>
wrote:
>
> I am attempting to write a simple Bash script that will find all the
> '*.pem' files in a directory structure and move them to another
> directory. It seems to work until I get to the copy part where it fails.
>
> My scripting skills are not that good. Perhaps someone could tell me
> what I am doing wrong.
>
> This is the script:
>
># ! /usr/bin/env bash
>
># Save the field separator
> oIFS=$IFS
>
># Set it to line breaks
> IFS=$'\n'
>
> for i in $(find ./ -name "*.pem" -print); do
>
># Get the basename
> BN=$(basename $i)
>
># copy the file to another directory using the base name
> cp $i /usr/home/tmp/$BN
>
> done
>
># Reset the IFS variable
> IFS=$oIFS
>
> exit
>
When I write scripts, I test them on the commandline to see if they're doing
what I think they're doing. I don't get the $(find ....) construction. You're
invoking find from within a for loop to return a value. Use backticks.
This works.
for i in `find ./ -name "*.pem" -print`
do
foo
bar
done
--
Paul Schmehl (pauls at utdallas.edu)
Senior Information Security Analyst
The University of Texas at Dallas
http://www.utdallas.edu/ir/security/
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