simple sh scripting. How to put a result of a command to a variable?
Constantine
cnst at rbcmail.ru
Mon Aug 11 14:49:25 PDT 2003
Hello!
I am writing a script, which involves unzipping some files. I would have
to unzip 4 different zip-files from some directory, and I would need to
unzip them to the directory, which would have the same name in it as the
original zip-file, i.e. I would like to run something like "ls *.zip",
have each file name recorded in some variable, and do a loop like "unzip
$filename[$i] -d $filename[$i].unzipped/". Can someone help me with the
code? How can I put the results of a command to a variable?
Cheers,
Constantine.
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