kern/73852: Not htonl() but ntohl()

KIYOHARA Takashi kiyohara at kk.iij4u.or.jp
Thu Nov 11 21:10:28 PST 2004


>Number:         73852
>Category:       kern
>Synopsis:       Not htonl() but ntohl()
>Confidential:   no
>Severity:       serious
>Priority:       high
>Responsible:    freebsd-bugs
>State:          open
>Quarter:        
>Keywords:       
>Date-Required:
>Class:          change-request
>Submitter-Id:   current-users
>Arrival-Date:   Fri Nov 12 05:10:27 GMT 2004
>Closed-Date:
>Last-Modified:
>Originator:     KIYOHARA Takashi
>Release:        
>Organization:
>Environment:
>Description:
see sys/net/if_fwsubr.c::firewire_input().
Why does it perform htonl() at the time of input of a packet?
An input packet is a network-byte-order. We should use ntohl().
>How-To-Repeat:
      
>Fix:
sys/net/if_fwsubr.c::firewire_input()
-------------------------------------
void
firewire_input(struct ifnet *ifp, struct mbuf *m, uint16_t src)
{

      ... snip ...

	/*
	 * Byte swap the encapsulation header manually.
	 */
-	enc->ul[0] = htonl(enc->ul[0]);
+	enc->ul[0] = ntohl(enc->ul[0]);

	if (enc->unfrag.lf != 0) {
		m = m_pullup(m, 2*sizeof(uint32_t));
		if (!m)
			return;
		enc = mtod(m, union fw_encap *);
-		enc->ul[1] = htonl(enc->ul[1]);
+		enc->ul[1] = ntohl(enc->ul[1]);
		m = firewire_input_fragment(fc, m, src);

>Release-Note:
>Audit-Trail:
>Unformatted:


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