> On Nov 1, 2015, at 20:15, Adrian Chadd <adrian.chadd at gmail.com> wrote: > > well, there's one cpu, nbuf=128, so lofreebuffers will be > MIN(nbuf/25+20, 128); nbuf=128, so it'll be 25. > hifreebuffers will be .. (3*25)/2, so 37. The values calculated via the old formulas were 12 and 24, BTW. What’s your maxbufspace set to?