Value of $? lost in the beginning of a function.

[Romain Tartière]

Hi Glen,

On Sun, Jul 19, 2009 at 04:32:28PM -0400, Glen Barber wrote:
> > % sh foo.sh
> > % zsh foo.sh
> > % bash foo.sh
> What happens if you replace '#!/bin/sh' with '#!/usr/local/bin/zsh' ?

This is not related to my problem since I am not running the script
using ./foo.sh but directly using the proper shell.  sh just behaves
differently, that looks odd so I would like to know if it is a bug in sh
or if there is no specification for this and the behaviour depends of
the implementation of each shell, in which case I have to tweak the
script I am porting to avoid this construct (passing $? as an argument
for example).

Romain

-- 
Romain Tartière <romain at blogreen.org>        http://romain.blogreen.org/
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