zfs quota question

[lhmwzy]

OK.It's my mistake.
Improve it again:

#!/bin/sh
find $1 -type f -ls  | awk '{j += $7} END {printf("%.2fM\n",j/1024/1024)}'

2008/10/8 Ian Smith <smithi at nimnet.asn.au>:
> On Wed, 8 Oct 2008, lhmwzy wrote:
>  > The fllow is better?
>  > #!/bin/sh
>  > find $1 -type f -exec ls -lh {} \; | awk '{j += $5} END {print j"M"}'
>
> Review your 'ls -lh' output; what's 100Bananas + 10Kiwifruit + 1Melon?
>
> $ find . -type f -exec ls -lh {} \; | awk '{j += $5} END {print j"M"}'
> 1.15975e+06M
>
> Took several minutes to come up with the wrong answer :)
>
> $ /root/bin/dirsize .
> 6906276646
>
> Took 2.75 seconds, giving actual total of the file sizes.
>
> $ du -d0 .
> 6781976 .
>
> Took 1.5 seconds, and comes to 69447434424, ie bytes allocated for those
> files.  All on a 300MHz Celeron.
>
>  > 2008/10/7 Andrew Snow <andrew at modulus.org>:
>  > >> I love ZFS, but I suddenly found out last night that I
>  > >> have lost the ability tto do a 'du' on a directory to work out if it will
>  > >> fit onto a CD or not :-)
>  > >
>  > > I have created a shell script, /usr/local/bin/dirsize :
>  > >
>  > > #!/bin/sh
>  > > find $1 -type f -ls | awk '{j += $7} END {print j}'
>  > >
>  > > Usage: dirsize <path>
>
> And very handy it is too, even without compressed ZFS, thanks Andrew.
>
> cheers, Ian
>