Interesting $0 Problem
jd1008 at gmail.com
Fri Oct 28 02:21:28 UTC 2016
That's because your PATH variable first searched /usr/local/bin
so that is the name of the shell that is running.
For example, from the command line:
$ echo $0
and my PATH variable looks like this:
$ echo $PATH
So, my entry in the password file says my shell is /bin/ksh
$ grep jd /etc/passwd
On 10/27/2016 07:53 PM, Tim Daneliuk wrote:
> On 10/27/2016 08:49 PM, Dutch Ingraham wrote:
>> On Thu, Oct 27, 2016 at 08:30:40PM -0500, Tim Daneliuk wrote:
>>> I was fidding with some shell code today and discovered it was breaking
>>> because $0 was returning "-/usr/local/bin/bash". Why is there a leading
>>> dash here? I've not seen that before.
>> How are you invoking the expansion, i.e., from a file or the
>> command-line? Is this a login shell?
>> What do you get from the command-line with <echo "$0">?
>> freebsd-questions at freebsd.org mailing list
>> To unsubscribe, send any mail to "freebsd-questions-unsubscribe at freebsd.org"
> My .bashrc source as standard startup profile:
> . mystartup
> Inside mystartup the folloing statement exists:
> source foo.sh
> $0 as reported in foo.sh is coming back with "-/usr/local/bin/bash"...
More information about the freebsd-questions