sed help please

[Guy TABRAR]

# echo -e "line1\nline2\nfoo\nline4\nline5\nbar\nline7" | sed -n '/foo/,/bar/p'
foo
line4
line5
bar

Regards

Guy 

-----Original Message-----
From: owner-freebsd-questions at freebsd.org [mailto:owner-freebsd-questions at freebsd.org] On Behalf Of David Banning
Sent: 04 March 2016 04:06
To: questions at freebsd.org
Subject: sed help please

I am trying to change hundreds of lines of text. Given the following text;

line 1
line 2 foo take this text
line 3
line 4
line 5 bar leave this text
line 6
line 7
 
I need a sed command that would take everything between foo and bar - including foo and bar.  

Ideally the output would look like;

line 1
line 2
leave this text
line 6
line 7

Keep in mind that foo and bar appear in different locations - sometimes at the beginning of a line, sometimes at the end, and sometimes in the middle.  I found someone who posted the following solution;

sed '/foo/,/bar/{s/./x/g}' file

but I found that this does not execute under FreeBSD.  I have looked around for differences between FreeBSD and other unix like SED operations but only see the -s "", regarding backup file.

Any pointers would be helpful.


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