Bourne variable unset outside while()

[Ivailo A. Tanusheff]

Hi,

I think you can check out this:
http://stackoverflow.com/questions/7482510/variable-incrementing-in-bash

So I sugest you do the same trick or use different approach - awk or something like this.

Regards,

Ivailo Tanusheff

-----Original Message-----
From: owner-freebsd-questions at freebsd.org [mailto:owner-freebsd-questions at freebsd.org] On Behalf Of Rick Miller
Sent: Thursday, May 08, 2014 9:48 PM
To: FreeBSD Questions
Subject: Bourne variable unset outside while()

Hi all,

I have a Bourne shell script that echoes the contents of a data structure to a while() loop that iterates over the data and is expected to append a string from the current iteration to a different list.  Inside the while(), it works fine, but echo'ing the list outside the loop produces empty output.  I expect the variable to maintain it's final state after processing the while(), but it does not appear to be doing so.

/** The script **/

#! /bin/sh -x

fs="freebsd-ufs gprootfs 1G
freebsd-swap gpswapfs 1G
freebsd-ufs gpvarfs 1G";

echo "${fs}" |
while read -r fstype fslabel fssize; do

        labels="${labels} ${fslabel}";
        echo "${labels}";

done

echo -e "\nlabels = ${labels}";

/** End the script **/

The output from this script is at http://pastebin.com/mxNLLWtm

This almost appears to be an issue with scope, but I've not encountered this before, especially in such simple context.  I must be missing something obvious and just looking for feedback to send me off in the right direction.

--
Take care
Rick Miller
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