/bin/sh script not behaving as expected
Cary
cary at SDF.ORG
Fri Aug 15 01:56:20 UTC 2014
On Thu, Aug 14, 2014 at 11:51:53AM -0600, Warren Block wrote:
> On Thu, 14 Aug 2014, Rick Miller wrote:
>
> >Hi all,
> >
> >I have shell code whose purpose is to determine the first disk in the
> >system where FreeBSD is to be installed. The code is not behaving as
> >expected and I?m hoping that fresh pairs of eyes might help me identify the
> >problem.
> >
> >Here is the script along with an explanation of the implementation and
> >description of the problem:
> >
> >#! /bin/sh
> >
> >disks="da2 da1 da0";
> >
> >for d in ${disks}; do
> > if [ -z "${disk}" -o "${disk}" '>' "${d}" ]; then
> > : ${disk:=${d}};
> > fi
> >done
>
> The algorithm is not clear to me,
Nor me.
Rick, I don't understand the test. Would just
if [ -z "${disk}" ]; then
suffice ? Single-quoting the > operator looks like an error that would have
prevented the shell from executing the script.
> but I would do something simpler like
>
> disk=`cd /dev; ls da? | head -n1`
>
> or, more correctly,
>
> disk=`sysctl -n kern.disks | tr " " "\n" | sort | head -n1`
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--
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