dhcp server returns core dump when i define network with mask 8

[J.McKeown at ru.ac.za]

Quoting Frank Leonhardt <frank2 at fjl.co.uk>:

>
> There are two common ways of defining a subnet mask - one is a  
> dotted quad (e.g. 255.255.255.0) and the other is with a slash and  
> the number of low-order bits - e.g. 192.168.1.0/8. Eight bits here  
> means you get 2^8 addresses (i.e. 256). Don't use the first and last  
> address in the range - the first is "complicated" (the network  
> address) and the last is for broadcast packets. This doesn't always  
> hold true but you're unlikely to come across exceptions.

This is the wrong way round. the number after the slash indicates the  
number of bits in the network address - the high-order bits.

> So, when you say you want to define a "network with mask 8" I don't  
> really know what you mean from your example. Do you mean a /8?
>
> 192.168.1.0/8 = range 192.168.1.1    192.168.1.254 with a subnet  
> mask of 255.255.255.0 (0xFFFFFF00)

Nope. 192.168.1.0/24 = 192.168.1.1-255 mask 255.255.255.0.  
192.168.1.0/8 doesn't start where you think it does (and is arguably  
the wrong way to specify that network) because all but the first 8  
bits are masked out - it's 192.0.0.0 - 192.255.255.255.