shell scripting: grepping multiple patterns, logically ANDed
Aleksandr Miroslav
alexmiroslav at gmail.com
Wed Jun 27 14:25:48 UTC 2012
hello,
I'm not sure if this is the right forum for this question, but here
goes.
I have the following in a shell script:
#!/bin/sh
if [ "$#" -eq "0" ]; then
find /foo
fi
if [ "$#" -eq "1" ]; then
find /foo | grep -i $1
fi
if [ "$#" -eq "2" ]; then
find /foo | grep -i $1 | grep -i $2
fi
if [ "$#" -eq "3" ]; then
find /foo | grep -i $1 | grep -i $2 | grep -i $3
fi
Is there an easier/shorter way to do this? If there are 15 arguments
supplied on the command line, I don't necessarily want to build 15 if
statements.
Thanks in advance for your answers.
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