sed argument processing b0rked?

[Lars Kellogg-Stedman]

>> sed -i'' -e 's/^\(REVOKE ALL ON SCHEMA public FROM \)postgres/\1pgsql/' \
> ?          -e 's/^\(GRANT ALL ON SCHEMA public TO \)postgres/\1pgsql/'    \
> ?          /tmp/pgdump
> sed: -e: No such file or directory

If you put a space after -i:

  sed -i '' ...

It will work.  The '-i' option takes an argument, and if you put a
null argument right next to it, with no spaces, the shell doesn't see
anything there.  That is, this:

  -i''

Is exactly equivalent to this:

  -i

Which means that sed is consuming the following argument as the
extension...so the first '-e' is the argument to the '-i' option.

-- Lars