How to obtain which interrupt take whole CPU

[illoai at gmail.com]

2010/10/16 Коньков Евгений <kes-kes at yandex.ru>:
> Hi
>
> #systat -v
>    1 users    Load  0,99  1,03  1,01                  16 окт 18:21
>
> Mem:KB    REAL            VIRTUAL                       VN PAGER   SWAP PAGER
>        Tot   Share      Tot    Share    Free           in   out     in   out
> Act  141700    4756   426408     6172   82400  count
> All  221700    7588  2581596    16556          pages
> Proc:                                                            Interrupts
>  r   p   d   s   w   Csw  Trp  Sys  Int  Sof  Flt        cow    2122 total
>             35      9495   64 1892       11k    1        zfod        atkbd0 1
>                                                          ozfod       ata0 14
> 34,2%Sys  47,3%Intr  3,4%User  0,0%Nice 15,1%Idle        %ozfod       ata1 15
> |    |    |    |    |    |    |    |    |    |    |       daefr       sis0 19
> =================++++++++++++++++++++++++>                prcfr  2122 cpu0:timer
>                                         3 dtbuf          totfr
> Namei     Name-cache   Dir-cache     41680 desvn          react
>   Calls    hits   %    hits   %     34874 numvn          pdwak
>       7       7 100                  9651 frevn          pdpgs
>                                                          intrn
> Disks   ad0                                        103632 wire
> KB/t   0,00                                         63940 act
> tps       0                                        247412 inact
> MB/s   0,00                                            12 cache
> %busy     0                                         82388 free
>
>
> How to obtain which interrupt take whole CPU?
>
>

vmstat -i
perhaps?

Я надеюсь, что это помогает.

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