pf rules

Doug Hardie bc979 at lafn.org
Fri Jan 22 23:34:50 UTC 2010


On 22 January 2010, at 03:14, Erik Norgaard wrote:

> Doug Hardie wrote:
>> On 22 January 2010, at 01:45, Erik Norgaard wrote:
>>> To debug pf rules:
>>> 
>>> - always add direction to the rule, pass or block, add interface to all
>>> rules except default policy, keep state on all pass rules
>>> - group your rules per direction, then per interface
>>> - add log to all rules and watch pflog to see which rule blocks or
>>> passes traffic.
>>> - use keyword quick for any decisive rule
>>> - check the parsing of your ruleset, pfctl -sr
>>> 
>>> then come back and ask for help.
>> Where do you find the rule information in the pflog output from tcpdump?  
> 
> a snip:
> 
> alpha# tcpdump -n -e -i pflog0
> tcpdump: WARNING: pflog0: no IPv4 address assigned
> tcpdump: verbose output suppressed, use -v or -vv for full protocol decode
> listening on pflog0, link-type PFLOG (OpenBSD pflog file), capture size 96 bytes
> 11:55:20.910140 rule 81/0(match): block in on vr1: 172.16.1.127.52444 > 172.16.0.1.23:  tcp 44 [bad hdr length 0 - too short, < 20]
> 
> rule 81 blocks. Now, problem is that your rules may be more compact, you'll find the rule with pfctl -sr. Now admittedly, I got:
> 
> pass in quick on vr1 inet proto udp from 172.16.0.0/23 to <local_ip> port = secret_service keep state
> 
> ofcourse, that rule didn't block. But two lines down I found:
> 
> block return in log quick on vr1 inet from 172.16.0.0/23 to <local_ip>
> 
> This makes sence, so why the offset 2? The first line of the output from pfctl -sr is
> 
> scrub all fragment reassemble
> 
> that shouldn't count as a rule. And then, if pflog starts counting with 0 while vi counts from 1 that explains it.
> 
> Yet another reason to check the rules as parsed using pfctl -sr.
> 
> Anyway, not trying to cut corners is the first step, then add log so you can see whats going on, use quick to avoid some packet fall through and being matched by a different rule than intended, organizes your rules so you can easily separate things out.
> 
> My rules are grouped together like this:
> 
> # default policy
> block all
> 
> block in log <general condition>
> pass  in quick some packets keep state
> block in log quick <general condition>
> 
> block out log <general condition>
> pass  out quick some packets keep state
> block out log quick <general condition>
> 
> # Default policy catch all should never apply
> block log all
> 
> the conditions for the pass rules should match those of the first block and then be more specific, say, only apply to one port. Doing so, the pf rule parser will optimize the ruleset.
> 
> Even if I know that a given rule can only match packets on the vr0 interface, I explicitly state the interface. It makes it clear what's going on.
> 
> Once the ruleset is debugged and working you can remove the log statements.
> 
> BR, Erik
> -- 

This is quite interesting.  I can't figure out the rules on my system.  Here is the pf.conf file with all comments removed:

table <blackhole> persist file "/etc/blackhole"
table <spamd> persist
table <spamd-white> persist
table <spamd-white-local> persist file "/etc/mail/whitelist"
MAILHOSTS = "{zool.lafn.org}"

no rdr on { lo0, lo1 } from any to any
no rdr inet proto tcp from <spamd-white-local> to any port smtp
no rdr inet proto tcp from <spamd-white> to any port smtp
rdr pass log inet proto tcp from any to any port smtp -> 127.0.0.1 port spamd
pass in log inet proto tcp to $MAILHOSTS port smtp keep state
pass in log on sis0 reply-to (sis0 192.168.25.1) proto tcp from any to any port 75 keep state
block in quick log on $ext_if from <blackhole> to any

Note:  the blackhole file is empty as is the whitelist file.  There is an entry for 216.54.240.150 in spamd database.  This is a test system.

Here is the output of tcpdump where I have only taken one entry for each rule.  I have listed the rule number at the front of each line:

Rule 0:  14:01:27.133320 rule 0/0(match): pass in on dc0: 216.54.240.150.55782 > 206.117.18.7.25: S 2501333595:2501333595(0) win 65535 <mss 1460,nop,nop,sackOK>
Rule 1:  02:26:44.755650 rule 1/0(match): pass in on sis0: 71.109.144.133.40864 > 192.168.25.7.75: S 3941268770:3941268770(0) win 65535 <mss 1460,nop,wscale 3,nop,nop,timestamp[|tcp]>
Rule 2:  10:44:45.037918 rule 2/0(match): block in on dc0: 71.109.162.173.39529 > 206.117.18.7.75: . ack 145 win 65535 <nop,nop,timestamp 705571170 1951648775>
Rule 4:  13:51:16.022700 rule 4/0(match): rdr in on dc0: 216.54.240.150.49821 > 127.0.0.1.8025: S 2371633783:2371633783(0) win 65535 <mss 1460,nop,nop,sackOK>

I found no entries for rule 3.  There is virtually no traffic on this system other than from me.


As I look at pf.conf and tie the rules to the entries I get (rule number at beginning of line):

no rdr on { lo0, lo1 } from any to any
no rdr inet proto tcp from <spamd-white-local> to any port smtp
0 - no rdr inet proto tcp from <spamd-white> to any port smtp
4 - rdr pass log inet proto tcp from any to any port smtp -> 127.0.0.1 port spamd
pass in log inet proto tcp to $MAILHOSTS port smtp keep state
1 - pass in log on sis0 reply-to (sis0 192.168.25.1) proto tcp from any to any port 75 keep state
block in quick log on $ext_if from <blackhole> to any


I have no clue which one is rule 2.  The only block is the last entry but that should never be used because the blackhole file is empty.  pfctl shows the table is empty also.

The ordering seems to make no sense either.  I also note that the man page for pf.conf indicates in the BNF grammar for pf.conf that log is a valid entry for no rdr.  However, that always generates a syntax error.  Apparently there is no way to log the use of no rdr rules.


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