Bash Script Help - File Names With Spaces -- SOLVED

[Drew Tomlinson]

On 8/17/2010 7:47 AM, Drew Tomlinson wrote:
> I have a collection of yearly top 100 Billboard mp3s in this format 
> (all one line - sorry if it wraps):
>
> /archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 
> Kenny Loggins - This Is It.mp3
>
> I want to create symbolic links to the top 30 in 1966-1969 in another 
> directory for easy migration to a flash card. Thus I invoked 'find' to 
> get a list (again, all one line):
>
> find -E "/archive/Multimedia/Audio/Music/Billboard Top USA Singles" 
> -regex '.*19[6-9][0-9]-0[0-2][0-9].*'
>
> (OK, I know this will only return the top 29)
>
> 'find' returns the complete filename as above:
>
> /archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 
> Kenny Loggins - This Is It.mp3
>
> Then I attempt to use 'basename' to extract the file name to a 
> variable which I can later pass to 'ln'.  This seems to work:
>
> basename "/archive/Multimedia/Audio/Music/Billboard Top USA 
> Singles/1980-028 Kenny Loggins - This Is It.mp3"
>
> returns (all one line):
>
> 1980-028 Kenny Loggins - This Is It.mp3
>
> which is what I would expect.  However using it with 'find' give me 
> this type of unexpected result:
>
> for i in `find -E "/archive/Multimedia/Audio/Music/Billboard Top USA 
> Singles" -regex '.*19[6-9][0-9]-0[1-2][0-9].*'`; do basename "${i}";done
>
> 1980-028
> Kenny
> Loggins
> -
> This
> Is
> It.mp3
>
> Why is this different? And more importantly, how can I capture the 
> file name to $i?

It finally occurred to me that I needed the shell to see a new line as 
the delimiter and not whitespace. Then a simple search revealed my answer:

O=$IFS
IFS=$(echo -en "\n\b")
<do stuff>
IFS=$O

Sorry for the noise.

Drew

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