and now for conky & gremlins
PJ
af.gourmet at videotron.ca
Thu Nov 5 15:41:24 UTC 2009
Ruben de Groot wrote:
> On Thu, Nov 05, 2009 at 09:26:15AM -0400, PJ typed:
>
>> Polytropon wrote:
>>
>>> On Wed, 04 Nov 2009 18:25:58 -0400, PJ <af.gourmet at videotron.ca> wrote:
>>>
>>>
>>>> output should be: 1 2 3 [4] 5 6 7 etc.
>>>> is: 1 2 3 4 5 6....
>>>>
>>>> the calendar.sh is exactly:
>>>> #!/bin/sh
>>>> cal | awk 'NR>1' | sed -e 's/ / /g' -e 's/[^ ] /& /g' -e 's/..*/
>>>> &/' -e "s/\ `date +%d`/\[`date +%d`\]/"
>>>>
>>>>
>>> It's quite obviously. Let's try the last substitution
>>> argument in plain shell:
>>>
>>> % date +%d
>>> 05
>>>
>>> But the command creates this:
>>>
>>> Su Mo Tu We Th Fr Sa
>>> 1 2 3 4 5 6 7
>>>
>>> The leading zero is missing, so there's no substition that
>>> changes "5" into "[5]", because the search pattern is "05".
>>>
>>>
>> Ok, I see... I'm not too good in programming. I guess I didn't notice
>> the previous to the first days of November the date was always 2
>> digits.. how do I get rid of the zero? Regex substitution or something
>> like that?
>>
>
> date "+%e" should do it.
>
Sure did.... For the moment, I changed the [ ] to just plain >
maybe that will avoid the disjointed row.
But changing the color of the current date sure would be nice... but is
there a way to do that?
More information about the freebsd-questions
mailing list