shell command line argument + parsing function

[Bill Campbell]

On Mon, Aug 31, 2009, Stefan Miklosovic wrote:
>hi,
>
>assuming I execute shell script like this
>
>$ ./script -c "hello world"
>
>I want to save "hello world" string to variable COMMENT in shell script.
>
>code:
>
>#!/bin/sh
>
>parse_cmdline() {
>    while [ $# -gt 0 ]; do
>        case "$1" in
>            -c)
>                shift
>                COMMENT="$1"
>                ;;
>        esac
>        shift
>    done
>}
>
>parse_cmdline $*
>
>echo $COMMENT
>
>exit 0
>
>but that only write out "hello". I tried to change $* to $@, nothing
>changed.

Did you put $@ in quotes?  That is parse_cmdline "$@".  I haven't
tried this in calling functions in scripts, but use it frequently
when calling scripts from other scripts.  I would probably use
something like:

for arg in "$@"; do
	dosomething "$arg"
done

Bill
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