Mentor for C self study wanted

Garrett Cooper youshi10 at
Tue Oct 23 19:00:57 PDT 2007

Bruce Cran wrote:
> cpghost wrote:
>> There's a mismatch here: scanf("%d", ...) expects a pointer to int,
>> while &nnote is a pointer to a short. Normally, an int occupies more
>> bytes in memory than a short (typically sizeof(int) == 4 on 32bit
>> platforms, and sizeof(int) == 8 on 64bit platforms; while typically
>> sizeof(short) == 2).
> I think short and int stay the same on both 32 and 64 bit platforms, 
> while it's only long that gets bumped to 8 bytes.  At least that seems 
> to be what happens on FreeBSD amd64.
> -- 
> Bruce
No... you're only safe using int32, int64, etc. Just for grins try 
compiling a program like this:

#include <stdio.h>

int main() {
    printf("%d\n", sizeof(int));
    return 0;

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