/bin/sh Madness
Tim Daneliuk
tundra at tundraware.com
Fri Feb 17 08:42:13 PST 2006
Dan Nelson wrote:
> In the last episode (Feb 16), Tim Daneliuk said:
>
>>Here is a shell function that behaves quite strangely:
>>
>>#!/bin/sh
>>#####
>># Execute A Command, Noting Start/Stop Time, & Logging Output
>># Args:
>># $1 Command Name
>># $2 Log Directory
>># $3 Command String To Execute
>>#####
>>
>>runupd()
>>{
>> log=$2/$1.log
>> timestamp $log
>> touch $2/.$1-begin && eval $3 2>&1 >> $log && touch $2/.$1-end &
>>}
>># End of 'runupd()'
>>
>>So, you might do something like:
>>
>> runupd freespace /var/log/ "df -k"
>>
>>Now, for the weirdness. This function works fine in my script
>>so long as one of two conditions is met:
>>
>> 1) I run it interactively from the command line (bash)
>> OR
>> 2) I run it from 'cron' AND $3 is *not* another script
>>
>>If I try to run it from 'cron' and point $3 to a script, everything gets
>>run as planned, however, the ending timestamp (touch $2/.$1-end) never
>>runs. That is, the initial time stamp (.$1-begin) and the command itself
>>are executed, and output is properly written to the logfile,
>>but the final timestamp never happens.
>
>
> Could your $3 command be returning a nonzero exit code? You probably
> want something more like
>
> touch $2/.$1-begin && { eval $3 2>&1 >> $log ; touch $2/.$1-end } &
I am looking into this.
>
> so your end timestamp always gets created whether or not $3 succeeds.
> Also note that in your original script, you only backgrounded "touch
> $2/.$1-end", which is probably not what you wanted.
Hmmmm - I have invoked the script that uses this function a variety
of ways and the command being evaled *is* being backgrounded in
every case with the syntax shown above ...
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Tim Daneliuk tundra at tundraware.com
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