Cron Job will not run.

[Giorgos Keramidas]

On 2005-11-03 16:33, Brandon Hinesley <brandonh at hotandcold.biz> wrote:
>
> Okay, the problem seems to be with a certain part of my script.
> Like I said, it works fine when I start it manually (./)
>
> I set up a few "checkpoints" if you will, and I determined that
> it's this loop that cron has a problem with:
>
> for (( i = $numbkups ; i >= 2 ; i-- ))
> do
>     let from=i-1
>     mv -fv $dbkups/$from $dbkups/$i
> done
>
> This loop never runs and neither does anything after it.  I
> don't see why cron would have any problem with this, or why
> this would exit the script...

Hmmm, what shell is this supposed to run in?
It doesn't look like /bin/sh syntax to me.