Cron Job will not run.
keramida at ceid.upatras.gr
Fri Nov 4 01:29:42 GMT 2005
On 2005-11-03 16:33, Brandon Hinesley <brandonh at hotandcold.biz> wrote:
> Okay, the problem seems to be with a certain part of my script.
> Like I said, it works fine when I start it manually (./)
> I set up a few "checkpoints" if you will, and I determined that
> it's this loop that cron has a problem with:
> for (( i = $numbkups ; i >= 2 ; i-- ))
> let from=i-1
> mv -fv $dbkups/$from $dbkups/$i
> This loop never runs and neither does anything after it. I
> don't see why cron would have any problem with this, or why
> this would exit the script...
Hmmm, what shell is this supposed to run in?
It doesn't look like /bin/sh syntax to me.
More information about the freebsd-questions