awk print

[Soheil Hassas Yeganeh]

You can set $[1..n] to "" and then print 
find ./ -name "stuff" | awk '{ $1=""; $2=""; print}


On Wed, 23 Feb 2005 22:41:32 -0500, Mark Frank <mark at mark-and-erika.com> wrote:
> * On Wed, Feb 23, 2005 at 07:36:05PM -0700 David Bear wrote:
> > On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:
> > > On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:
> > > > I'm using awk to parse a directory listing. I was hoping there is a
> > > > way to tell awk to print from $2 - to the end of the columns
> > > > available.
> > > >
> > > > find ./ -name '*stuff' | awk '{FS="/" print $3---'}
> > >
> > > Is this what you mean?:
> > >
> > > find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'
> >
> > thanks for the advice. No, this doesn't do what I want.
> >
> > If I have a directory path /stuff/stuff/more/stuff/more/and/more
> > that is n-levels deep, I want to be able to cut off the first two
> > levels and print the from 2 to the Nth level.
> 
> So how about cut?
> 
> find ./ -name '*stuff'| cut -d/ -f4-
> 
> Mark
> 
> --
> "The fix is only temporary...unless it works." - Red Green
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