An AWK question

Steven Friedrich FreeBSD at insightbb.com
Fri Feb 4 12:24:04 PST 2005


On Friday 04 February 2005 02:14 pm, antenneX wrote:
> ---> FBSD-4.10p2
>
> I have a script that tells me when a mailbox exceeds 2MB. Using it for
> another purpose. how can I modify this script to tell me when a file is
> LESS than a certain size?
>
> ---------------------------------------------
> #!/bin/sh
>
> #AWK=/usr/bin/awk
> #FILE=/file/size/to/check
> #LS=/bin/ls
> #SIZE=2048     # (2048 = 2MB)
>
> #if [ `${LS} -s ${FILE} | ${AWK} '{ print $1 }'` -gt ${SIZE} ]; then
> #    echo File ${FILE} is ABOVE normal | mail -s "Alert: Check the file"
> #fi
> ---------------------------------------------
>
> Thanks, and....
>
> Best regards,
>
> Jack L. Stone
>
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Jonathen's correct. It's not an awk question. It's actually being evaluated by 
test. see man test )test is also invoked when you see [ some equation ] (you 
need the space at least on the inside of [ and ], perhaps on the outsides 
too.
#if [ `${LS} -s ${FILE} | ${AWK} '{ print $1 }'` -lt ${SIZE} ]; then
#    echo File ${FILE} is BELOW normal | mail -s "Alert: Check the file"
#fi

awk is just being used to get the first field from ls -s, which is the size...
-- 
i386 FreeBSD 4.11-STABLE


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