MIDI timing

[Ralf Mardorf]

On Sat, 18 May 2019 17:56:27 +0200, Ralf Mardorf via freebsd-multimedia
wrote:
>On Sat, 2019-05-18 at 16:30 +0200, Clemens Ladisch wrote:
>> With 120 BPM, you actually have 2304000 ticks per second.  
>
>120 BPM = 2 seconds per bar
                     ^^^^^^^ assuming four-four time :D
However, 1/4 note always remains 500 ms.

>(60000ms/120BPM)*4=2000ms
>
>2304000ticks/120BPM=19200
>
>Wouldn't that mean 2304000 ticks per 2 seconds?