vmtotal consumes significant portion of cpu cycles
Allan Jude
allanjude at freebsd.org
Mon Oct 26 15:56:50 UTC 2015
On 2015-10-26 09:28, Jia-Shiun Li wrote:
> Hi all,
>
> I noticed that 'sysctl -vm 1' consumes about 5% cpu time on a machine with
> 2x 6-core Xeon E5v3 and 64GB memory. That's a lot for a monitoring tool.
>
> After digging a while I found that it is vmtotal() in kernel that consumes
> major cycles. When memory usage is high the cost of vmtotal() rises too. It
> is reproducible with sysctl when memory utilization is high:
>
> % time repeat 100 sysctl vm.vmtotal > /dev/null
> 0.055u 8.102s 0:08.19 99.5% 31+175k 0+0io 0pf+0w
>
> % top
> last pid: 40272; load averages: 0.32, 4.74, 8.01 up 3+01:19:54
> 17:23:59
> 58 processes: 1 running, 57 sleeping
> CPU: 0.1% user, 0.0% nice, 1.6% system, 0.1% interrupt, 98.3% idle
> Mem: 4509M Active, 52G Inact, 2819M Wired, 1572M Buf, 2930M Free
> Swap: 3598M Total, 3598M Free
>
> PID USERNAME THR PRI NICE SIZE RES STATE C TIME CPU
> COMMAND
> 46841 root 30 20 0 9248M 7930M kqread 9 20.8H 11.88% bhyve
> 49914 jsli 1 23 0 19320K 3884K select 5 134:08 4.79% systat
>
>
> In FreeBSD source tree systat and vmstat are major user. Other tools like
> bsnmpd may use it too via sysctl.
>
> I don't have idea yet how this can be improved. Shall I create a bug to
> keep track of it?
>
>
> -Jia-Shiun
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>
In the first 2 references you say 'sysctl', do you mean 'systat' in all
instances?
--
Allan Jude
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