Strange instructions in compiler output

[chungwei Hsiung]

thanks for the reply

compile the code by 

gcc -o shellcode -ggdb -static shellcode.c

actually giving me the code you showed below

I still don't understand it because we are supposed to pass in the op code 0xb to %eax, and arguments to %ebx, %ecx, and %edx before calling interupt, but I can't see any of those instruction anywhere. Did I miss anything?

best regards,
Chungwei



On Sat, 06 Mar 2004 21:31:51 +0100
des at des.no (Dag-Erling Smørgrav) wrote:

> Anthony Schneider <anthony at x-anthony.com> writes:
> > On Sat, Mar 06, 2004 at 02:26:51PM +0000, chungwei Hsiung wrote:
> > > gcc -o shellcode -ggdb -static shellcode.c
> > try compiling with the -static flag the gcc.
> 
> Reading is fast becoming a lost art...
> 
> Anyway, here's the code for execve():
> 
> 08048224 <__sys_execve>:
>  8048224:       b8 3b 00 00 00          mov    $0x3b,%eax
>  8048229:       cd 80                   int    $0x80
>  804822b:       72 ef                   jb     804821c <main+0x3c>
>  804822d:       c3                      ret
>  804822e:       90                      nop
>  804822f:       90                      nop
> 
> exciting, huh?  oh, and the code that calls it:
> 
>  8048201:       6a 00                   push   $0x0
>  8048203:       8d 45 f8                lea    0xfffffff8(%ebp),%eax
>  8048206:       50                      push   %eax
>  8048207:       ff 75 f8                pushl  0xfffffff8(%ebp)
>  804820a:       e8 15 00 00 00          call   8048224 <__sys_execve>
>  804820f:       83 c4 10                add    $0x10,%esp
> 
> DES
> -- 
> Dag-Erling Smørgrav - des at des.no
>