[head tinderbox] failure on mips/mips

M. Warner Losh imp at bsdimp.com
Wed Feb 18 07:22:21 PST 2009


In message: <20090218110402.GA13040 at duncan.reilly.home>
            Andrew Reilly <andrew-freebsd at areilly.bpc-users.org> writes:
: On Tue, Feb 17, 2009 at 10:21:52PM -0700, M. Warner Losh wrote:
: > In message: <20090217.203647.-1518647466.imp at bsdimp.com>
: >             "M. Warner Losh" <imp at bsdimp.com> writes:
: > : In message: <20090218023328.227617302F at freebsd-current.sentex.ca>
: > :             FreeBSD Tinderbox <tinderbox at freebsd.org> writes:
: > : : /src/usr.sbin/bsnmpd/modules/snmp_mibII/../../../../contrib/bsnmp/snmp_mibII/mibII.c:1016: warning: cast increases required alignment of target type
: > The first one is:
: > 
: > 	  case RTM_IFINFO:
: > 		ifm = (struct if_msghdr *)rtm;
: > 		mib_extract_addrs(ifm->ifm_addrs, (u_char *)(ifm + 1), addrs);
: > 		if ((ifp = mib_find_if_sys(ifm->ifm_index)) == NULL)
: > 			break;
: > 
: > rtm is of type struct rt_msghdr.  This has an alignment requirement of
: > 4 on mips, at least on 32-bit mips (the biggest data element is a
: > u_long).  struct if_msghdr has an alignment requirement of 8, because
: > time_t is int64_t on MIPS, which is 8-bytes in size.
: 
: If the memory that rtm can be pointing to can be either a struct
: rt_msghdr or a struct if_msghdr, then shouldn't it really be
: pointing to a union of those two, and then the alignment will
: sort itself out?  (As far as I know, that's the only way that
: C99 will guarantee that the right thing happens anyway,
: otherwise strict aliasing analysis would allow much worse
: badness to happen, potentially.)

This is a stream of data from the kernel, multiple messages, so making
it be a union wouldn't force the proper alignment from the kernel...

: Not looked at the code myself.  Perhaps there's a reason why
: that would be unworkable.

Yes.  There is.

Warner


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