[Bug 208169] [patch] df(1): df -l -l output "df: -l and -t are mutually exclusive."

bugzilla-noreply at freebsd.org bugzilla-noreply at freebsd.org
Mon Mar 21 03:02:19 UTC 2016


https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=208169

            Bug ID: 208169
           Summary: [patch] df(1): df -l -l output "df: -l and -t are
                    mutually exclusive."
           Product: Base System
           Version: 10.1-RELEASE
          Hardware: i386
                OS: Any
            Status: New
          Keywords: patch
          Severity: Affects Many People
          Priority: ---
         Component: bin
          Assignee: freebsd-bugs at FreeBSD.org
          Reporter: by at reorigin.com
                CC: freebsd-i386 at FreeBSD.org
          Keywords: patch
                CC: freebsd-i386 at FreeBSD.org

Created attachment 168442
  --> https://bugs.freebsd.org/bugzilla/attachment.cgi?id=168442&action=edit
Fix output message which does not specify the exact situation.

Overview:
If type command "df -l -l", the output will be:
df: -l and -t are mutually exclusive.

Obviously, the output message does not tell the truth.

I have created a patch which should fix this issue.

Thanks.

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