bin/171427: sh(1): Hitting ^Z doesn't suspend jobs like
expected
Jilles Tjoelker
jilles at stack.nl
Sun Sep 16 21:20:14 UTC 2012
The following reply was made to PR bin/171427; it has been noted by GNATS.
From: Jilles Tjoelker <jilles at stack.nl>
To: bug-followup at FreeBSD.org, yanegomi at gmail.com
Cc:
Subject: Re: bin/171427: sh(1): Hitting ^Z doesn't suspend jobs like
expected
Date: Sun, 16 Sep 2012 23:11:33 +0200
> [while : ; do netperf -cCjt TCP_STREAM -H 10.7.187.52 -l 10 -- -D; done
> works strangely with ^C/^Z]
For the case with ^C, I indeed deliberately fixed that for 9.0.
For the case with ^Z, this is indeed a caveat that is complained about
more frequently, and different shells handle it differently because
POSIX leaves it vague.
POSIX discusses suspending jobs (process groups), but a sequence or
while loop is not a job.
One workaround is to make it a job by placing parentheses around the
loop. With most shells, this creates a new process group and job that
can be suspended normally. An exception is ksh93 which attempts to
execute the subshell in the same process; I do not like this but I think
POSIX permits it (and in non-interactive or no-job-control mode it is
fine to execute a subshell in that way).
What sh does is return status 146 (128+SIGTSTP) and continue (so while
netperf; do :; done will abort if ^Z'ed).
What bash appears to do is break loops if something was ^Z'ed.
What zsh appears to do is fork and continue the loop after the suspended
process terminates. However, it gets $? wrong. Also, it needs a fair bit
of code and changes to the shell environment after the suspension do not
affect the parent.
--
Jilles Tjoelker
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