Unaligned access in ubldr.bin
Warner Losh
imp at bsdimp.com
Fri Sep 9 15:31:58 UTC 2016
On Thu, Sep 8, 2016 at 5:23 PM, Erik Moe <e.moe at rcn.com> wrote:
>
> On Sep 7, 2016, at 8:22 AM, Warner Losh <imp at bsdimp.com> wrote:
>
> On Wed, Sep 7, 2016 at 12:46 AM, Erik Moe <e.moe at rcn.com> wrote:
>
> Hello,
>
> I’ve been trying to bring up FreeBSD on the USB Armory based on the i.MX53.
> I’ve made myself a u-boot patch that will load and start ubldr.bin but I’m
> running into a issue with what I think is an unaligned access issue:
>
>
> which version of u-boot are you using?
>
>
> I was using 2016.07, but also tried u-boot from head (b615267).
When forward porting the u-boot in the ports tree, I noticed that 2016.05 worked
w/o changing anything in ubldr and 2016.07 and head from a week ago both
gave me unaligned accesses. Maybe you could try it as an experiment? Failed
in exactly the same way on the two boards I tried it on (pandaboard and BBB).
> ## Starting application at 0x70800000 ...
> data abort
> pc : [<70824bac>] lr : [<7081846c>]
> sp : 8f550c98 ip : 70835a00 fp : 8f550cb0
> r10: 00000002 r9 : 70838d58 r8 : 70833cd9
> r7 : 707fff08 r6 : 000054f0 r5 : 70833cd9 r4 : 00000000
> r3 : 70828fc4 r2 : 70833cd9 r1 : 00000001 r0 : 7083705c
> Flags: Nzcv IRQs off FIQs off Mode SVC_32
> Resetting CPU ...
>
> I’ve hand dissambled the code at pc=0x70824bac:
>
> 0x70824ba8: 0xe59f21d0 ldr r2, [pc, #464]
> 0x70824bac: 0xe5825000 str r5, [r2]
> 0x70824bb0: 0xe5d53000 ldrb r3, [r5]
> 0x70824bb4: 0xe353002d cmp r3, #45
> 0x70824bb8: 0x1a00000b bne #+44
>
> The offending instructions is "str r5, [r2]” where r2 = 0x70833cd9, which
> sort of makes sense since it isn’t aligned on a 4 byte boundary. I’m new to
> arm ARM, so I’m not really sure. My questions are these:
>
> 1.) Doesn’t ARMv6 and higher architecture allow unaligned access? Is there
> something that u-boot needs be doing in initialization to allow unaligned
> access?
>
>
> It does, but usually that's configured later in boot.
>
> 2.) Does ubldr make the assumption that unaligned access is allowed and
> maybe shouldn’t? I would think not since ubldr has been around for a while
> and works on numerous ARM processors.
>
>
> It may be that the compiler is generating bad code in this case? You
> might check to see how we're building it and to see if that's causing
> problems.
>
>
> Per Michal Stanek’s suggestion I tried adding "-mno-unaligned-access” to the
> build of ubldr. It’s still failing in getopt, though not it the same spot:
How about adding it to the ubldr build? IIRC, it should be default in
FreeBSD's clang though.
> ## Starting application at 0x70800000 ...
> data abort
> pc : [<70824bd0>] lr : [<70818454>]
> sp : 8f559a78 ip : 70835a90 fp : 8f559a90
> r10: 00000002 r9 : 70838df0 r8 : 70833d73
> r7 : 707fff08 r6 : 00005530 r5 : 70833d73 r4 : 00000000
> r3 : 70828fe8 r2 : 70833d73 r1 : 00000001 r0 : 708370ec
> Flags: Nzcv IRQs off FIQs off Mode SVC_32
> Resetting CPU ...
>
> 0x70824bcc 0xe59f21d0 ldr r2, [pc, #464]
> 0x70824bd0 0xe5825000 str r5, [r2]
> 0x70824bd4 0xe5d53000 ldrb r3, [r5]
> 0x70824bd8 0xe353002d cmp r3, #45
>
> 70833d72: 00 61 3a 00 55 42 6f 6f 74 41 50 49 00 49 44 .a:.UBootAPI.ID
>
> r2 contains 70833d73 which points to “0x61 0x3a 0x00”, which is the literal
> string “a:”. Looking at the lr register the calling function is
> “api_parse_cmdline_sig”. Looking at the code:
>
> api_parse_cmdline_sig(int argc, char **argv, struct api_signature **sig)
> {
> unsigned long api_address;
> int c;
>
> api_address = 0;
> opterr = 0;
> optreset = 1;
> optind = 1;
>
> while ((c = getopt (argc, argv, "a:")) != -1)
> switch (c) {
> case 'a':
> api_address = strtoul(optarg, NULL, 16);
> break;
> default:
> break;
> }
>
> It’s the third argument to getopt that seems to be on an odd address. As
> for the SCTLR.A bit being enabled, that is definitely something u-boot does,
> because the default state is for it to be cleared after reset. I see this
> in arch/arm/cpu/armv7/start.S:
>
> /*
> * disable MMU stuff and caches
> */
> mrc p15, 0, r0, c1, c0, 0
> bic r0, r0, #0x00002000 @ clear bits 13 (--V-)
> bic r0, r0, #0x00000007 @ clear bits 2:0 (-CAM)
> orr r0, r0, #0x00000002 @ set bit 1 (--A-) Align
> orr r0, r0, #0x00000800 @ set bit 11 (Z---) BTB
> #ifdef CONFIG_SYS_ICACHE_OFF
> bic r0, r0, #0x00001000 @ clear bit 12 (I) I-cache
> #else
> orr r0, r0, #0x00001000 @ set bit 12 (I) I-cache
> #endif
> mcr p15, 0, r0, c1, c0, 0
>
> I tried to clear that flag, but that didn’t work either, but I’m not sure if
> this is correct:
>
> mac p15, 0, r0, c1, c0, 0
> bic r0, r0, #0x00000002
> mar p15, 0, r0, c1, c0, 0
That looks like it should do the right thing. You could just remove
the orr line that ors in bit 1 too. Have you tried that?
Warner
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