git: 450f3e55bdad - stable/13 - Work around bogus old gcc "initializer element is not constant" error
Dimitry Andric
dim at FreeBSD.org
Sat Jun 26 13:37:09 UTC 2021
On 26 Jun 2021, at 06:11, Mark Millard <marklmi at yahoo.com> wrote:
>
> Dimitry Andric dim at FreeBSD.org wrote on
> Fri Jun 25 18:46:00 UTC 2021 :
>
> . . .
>> In file included from /workspace/src/lib/msun/src/s_llround.c:11:0:
>> /workspace/src/lib/msun/src/s_lround.c:54:31: error: initializer element is not constant
>> static const type dtype_min = type_min - 0.5;
>> ^~~~~~~~
>> /workspace/src/lib/msun/src/s_lround.c:55:31: error: initializer element is not constant
>> static const type dtype_max = type_max + 0.5;
>> ^~~~~~~~
>>
>> Since 'type_min' and 'type_max' are constants declared just above these
>> lines this error is nonsensical, but older gcc's are not smart enough.
> . . .
>
> Well, in C "const" historically means closer to "read-only" than
> to is-a-constant-expression in the language, unfortunately. Part
> of this is the conversion away from being an lvalue (so: where
> an lvalue is not required) loses the const qualification as part
> of the conversion.
FWIW, this changed in gcc 8.1+, here:
https://gcc.gnu.org/git/?p=gcc.git;a=commit;h=f9c59f7e9511856bd6dc13d2d4904ebd9249c095
referencing these bugs:
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66618
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=69960
In one of the comments, joseph at codesourcery.com mentions:
> Although diagnosing this probably makes sense, it's not required by the
> standard ("An implementation may accept other forms of constant
> expressions." - and this expression doesn't contain "assignment,
> increment, decrement, function-call, or comma operators", so isn't
> required by the Constraints for constant expressions not to be one).
I guess the gcc people also decided that POLA applied here. :)
-Dimitry
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