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Subject: Re: understanding the output of: gpart list da0
From: Doug Hardie <bc979@lafn.org>
In-Reply-To: <ZhDxHle8gRlBbipL@c720-1400094>
Date: Sat, 6 Apr 2024 01:47:56 -0700
Cc: freebsd-questions@freebsd.org
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To: Matthias Apitz <guru@unixarea.de>
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> On Apr 5, 2024, at 23:52, Matthias Apitz <guru@unixarea.de> wrote:
>=20
>=20
> Hello,
>=20
> I have here the output (a bit shorted and with added calculations)
> of 'gpart list da0':
>=20
> 1. Name: da0p1
>   Mediasize: 524288 (512K)   512K =3D 512*1024 =3D 524288 =3D length
>   index:  1
>   start:  1953523712
>   end:    1953524735
>   length: 524288
>=20
> 2. Name: da0p2
>   Mediasize: 274877906944 (256G)  256G =3D 256*1024*1024*1024 =3D =
274877906944 =3D length
>   index:  2
>   start:  2048
>   end:    536872959
>   length: 274877906944
>=20
> 3. Name: da0p3
>   Mediasize: 41943040 (40M)    40M =3D 40*1024*1024 =3D 41943040 =3D =
length
>   index:  3
>   start:  536872960
>   end:    536954879
>   length: 41943040
>=20
> 4. Name: da0p4
>   Mediasize: 723177701376 (674G)  674G =3D 674*1024*1024*1024 =3D =
723701989376 !=3D length
>   index:  4
>   start:  541067264
>   end:    1953523711
>   length: 723177701376
>=20
>=20
> What I do not understand is:
>=20
> 1) Why differs the 'length' of da0p4 from the real value for 674G?

723177701376 / 1024 / 1024 / 1024 =3D 673.51171875 which rounds up to =
674 G.

> 2) All the values for 'start', 'end' and 'length' does not make any
> sense to me.

(end - start + 1) *512 =3D length

>=20
> Can someone enlighten me a bit.

-- Doug