git: 57f6ba0e3878 - stable/13 - makefs: remove vestigial '?' cases from top-level getopt(3) loop

The branch stable/13 has been updated by emaste:

URL: https://cgit.FreeBSD.org/src/commit/?id=57f6ba0e387836c6d7356829d71c30ef96e914cb

commit 57f6ba0e387836c6d7356829d71c30ef96e914cb
Author:     Ed Maste <emaste@FreeBSD.org>
AuthorDate: 2023-03-30 01:33:39 +0000
Commit:     Ed Maste <emaste@FreeBSD.org>
CommitDate: 2023-04-14 12:10:36 +0000

    makefs: remove vestigial '?' cases from top-level getopt(3) loop
    
    getopt(3) returns '?' when it encounters a flag not present in the in
    the optstring or if a flag is missing its option argument.  We can
    handle this case with the "default" failure case with no loss of
    legibility.
    
    Obtained from:  OpenBSD makefs.c 1.22
    
    (cherry picked from commit cc4adc4c4e473d47b687d2ac2757157abd728c81)
---
 usr.sbin/makefs/makefs.c | 1 -
 1 file changed, 1 deletion(-)

diff --git a/usr.sbin/makefs/makefs.c b/usr.sbin/makefs/makefs.c
index 987f4159b403..7f23b8a6a5f1 100644
--- a/usr.sbin/makefs/makefs.c
+++ b/usr.sbin/makefs/makefs.c
@@ -270,7 +270,6 @@ main(int argc, char *argv[])
 			fsoptions.sparse = 1;
 			break;
 
-		case '?':
 		default:
 			usage(fstype, &fsoptions);
 			/* NOTREACHED */