Serious problems updating Current after switching to libxul.
Matthew Seaman
m.seaman at infracaninophile.co.uk
Tue Jan 19 08:51:21 UTC 2010
keneasson wrote:
>
> Can anyone help me get my system back up and running?
>
> make.conf looks like this:
> WITH_MYSQL_VER=51
> APACHE_VERSION=22
> OVERRIDE_LINUX_BASE_PORT=f8
> WWWDIR = /web/phpmyadmin
> WITH_CUPS="yes"
> CUPS_OVERWRITE_BASE=true
> #NO_LPR=true
> USE_GECKO=libxul
^^^^^^^^^^^^^^^^^
This is your problem. You want to say:
WITH_GECKO=libxul
here.
> # Begin portconf settings
> # Do not touch these lines
> .if !empty(.CURDIR:M/usr/ports*) && exists(/usr/local/libexec/portconf)
> _PORTCONF!=/usr/local/libexec/portconf
> .for i in ${_PORTCONF:S/|/ /g}
> ${i:S/%/ /g}
> .endfor
> .endif
> # End portconf settings
> # added by use.perl 2009-09-19 16:22:20
> PERL_VERSION=5.10.1
In general, you *never* add any USE_FOO flags to /etc/make.conf -- USE_FOO
is designed for use by port maintainers inside the limited scope of
port-specific Makefiles: the presence of a USE_FOO setting in scope
generally does dramatic things like adding dependencies on whole
software subsystems. Your 'USE_GECKO' setting in /etc/make.conf (which has
effect in the global scope) has made *every* port on your machine depend on
gecko related libraries. It's not really surprising you're experiencing a
bit of brokenness.
Instead, you need a WITH_FOO flag. WITH_FOO is designed for end users to
tweak the way ports work in detail: they only have any effect in ports that
are specifically written to take notice of them; everything else will just ignore them. Even so, it's very common to use directory matching login or,
as you have, things like PORTCONF to limit the application of a WITH_FOO
flag to a specific port. The whole OPTIONS dialogue system is just a
front-end to setting WITH_FOO flags for a specific port.
Note: something that may cause a certain amount of astonishment to neophyte
users. The opposite of saying:
WITH_FOO=yes
is not:
WITH_FOO=no ### Don't do this.
but:
WITHOUT_FOO=yes ### Do this.
That's because the value of 'WITH_FOO' variables is not actually tested
anywhere, only whether the variable is defined or not. Setting
WITH_FOO=bananas would have exactly the same effect, as, indeed does
WITH_FOO=no or WITH_FOO=over_my_dead_body
Cheers,
Matthew
--
Dr Matthew J Seaman MA, D.Phil. 7 Priory Courtyard
Flat 3
PGP: http://www.infracaninophile.co.uk/pgpkey Ramsgate
Kent, CT11 9PW
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