Extracting a variable listing

[Jack L. Stone]

At 10:53 AM 8.18.2010 -0300, A. Wright wrote:
>On Wed, 18 Aug 2010, Jack L. Stone wrote:
>
>> The content I need will always fall beneath a row of pound signs, and there
>> is content above that row I don't want, like this:
>>
>> bunch of rows I don't need here
>> ############################### <--- the top of stuff needed
>> row1
>
>
>If you want the '#' line in the output
> 	cat YourFile | sed -n -e '/#####/,$p'
>
>If you don't, then
> 	cat YourFile | sed -e '1,/#####/d'
>
>The above assumes that you will have at least 5 '#' chars on
>your divider line, and never before in the file.  Increase the
>number '#' symbols if the above example is strictly literal.
>Note the -n in the first line.
>
>A.
>

Worked like a charm, Andrew! Just what I needed!

Jack

(^_^)
Happy trails,
Jack L. Stone

System Admin
Sage-american