A question about the date Function
martin at dc.cis.okstate.edu
Wed Sep 16 20:25:17 UTC 2009
The man page on date has an example showing how to get
an output showing the number of seconds since the Epoch.
date -j -f "%a %b %d %T %Z %Y" "`date`" "+%s"
There is an envokation of date embedded in this command
I was curious as to what this command does so I tried the long
form and then the short form with:
date -j -f "%a %b %d %T %Z %Y" "`date`" "+%s" >f0
date +%s >f1
I then compared the outputs of f0 and f1 and they are identical.
What does the long form of this command give us that
date +%s fails to do?
Nothing is broken, here. I am just curious. Thank you.
Martin McCormick WB5AGZ Stillwater, OK
OSU Information Technology Department Telecommunications Services Group
More information about the freebsd-questions