and now for conky & gremlins
Polytropon
freebsd at edvax.de
Thu Nov 5 01:30:54 UTC 2009
On Wed, 04 Nov 2009 18:25:58 -0400, PJ <af.gourmet at videotron.ca> wrote:
> output should be: 1 2 3 [4] 5 6 7 etc.
> is: 1 2 3 4 5 6....
>
> the calendar.sh is exactly:
> #!/bin/sh
> cal | awk 'NR>1' | sed -e 's/ / /g' -e 's/[^ ] /& /g' -e 's/..*/
> &/' -e "s/\ `date +%d`/\[`date +%d`\]/"
It's quite obviously. Let's try the last substitution
argument in plain shell:
% date +%d
05
But the command creates this:
Su Mo Tu We Th Fr Sa
1 2 3 4 5 6 7
The leading zero is missing, so there's no substition that
changes "5" into "[5]", because the search pattern is "05".
--
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
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