Simple PAM authentication code?

[Rob Pitt]

This is mostly taken from Linux Standards Base. Compile with -lpam - 
lpam_misc.

HTH

- RP

#include <security/pam_appl.h>
#include <security/pam_misc.h>
#include <stdio.h>

int main(int argc, char *argv[])
{
         static struct pam_conv conv;
         conv.conv = misc_conv;
         conv.appdata_ptr = NULL;

         pam_handle_t *pamh;
         int pam_status;
         char *user;

         pam_status = pam_start("testing", NULL, &conv, &pamh);

         if (pam_status == PAM_SUCCESS)
                 pam_status = pam_authenticate(pamh, 0);

         if (pam_status == PAM_SUCCESS) {
                 pam_get_item(pamh, PAM_USER, (const void **)&user);
                 fprintf(stdout, "Greetings %s\n", user);
         } else {
                 printf("%s\n", pam_strerror(pamh, pam_status));
         }

         pam_end(pamh, pam_status);
}


On 30 Sep 2005, at 18:46, Brian J. McGovern wrote:

> Could someone point me at a short, straight forward bit of code that
> validates a given username and password via PAM? I've tried writing  
> a short
> app to make sure PAM is working the way I want to locally, but no  
> matter how
> good the info, I'm getting an authentication denied, so I know I'm
> missing something.
>
> The openpam site didn't seem to helpful documentation wise, and my  
> connection to
> download the source seems to be timing out at the moment...
>
>     -B
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