Cron Job will not run.
brandonh at hotandcold.biz
Fri Nov 4 00:32:37 GMT 2005
Okay, the problem seems to be with a certain part of my script. Like I
said, it works fine when I start it manually (./)
I set up a few "checkpoints" if you will, and I determined that it's this
loop that cron has a problem with:
for (( i = $numbkups ; i >= 2 ; i-- ))
mv -fv $dbkups/$from $dbkups/$i
This loop never runs and neither does anything after it. I don't see why
cron would have any problem with this, or why this would exit the script...
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