What is going on with ash / sh

[Mark Saad]

On Wed, Nov 2, 2011 at 4:35 PM, Doug Barton <dougb at freebsd.org> wrote:
> On 11/02/2011 13:28, Mark Saad wrote:
>> Hackers
>>  What is going on here, if I run the following shell script, what is
>> the expected output . The script is named xxx
>>
>> #!/bin/sh
>> ps -ax | grep -v grep | grep xxx
>>
>> Here is what I see
>>
>>
>>  # sh xxx
>> 88318  p0  S+     0:00.00 sh xxx
>> 88320  p0  R+     0:00.00 sh xxx
>> 88321  p0  R+     0:00.00 sh xxx
>>
>>
>> Can someone explain this ?
>
> I only see one. What happens if you run this on the command line?
>
>
if you run it from the command line you only see on process.

>
> --
>
>                "We could put the whole Internet into a book."
>                "Too practical."
>
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>



-- 
mark saad | nonesuch at longcount.org