sched_newthread question

Andrey Simonenko simon at comsys.ntu-kpi.kiev.ua
Mon Mar 6 01:28:52 PST 2006


On Sat, Mar 04, 2006 at 06:11:24PM +0100, Divacky Roman wrote:
> hi,
> 
> sched_newthread(struct thread *td)
> {
>            struct td_sched *ke;
> 
> 	ke = (struct td_sched *) (td + 1);
> 	bzero(ke, sizeof(*ke));
> 	td->td_sched     = ke;
> 	ke->ke_thread   = td;
> 	ke->ke_state    = KES_THREAD;
> }
> 
> whats the logic behind:
> ke = (struct td_sched *) (td + 1); ? 
> 
> shouldnt it be:
> ke = td -> td_sched; ?
> 

This function does exactly as the comment for it describes.
When memory is allocated for struct thread{}, then this
memory consists of two parts, one part is for struct thread{}
and next part is scheduler specific structure for this thread.

To get pointer to that scheduler specific data it is necessary
to point to the next byte after struct thread{}.  For more
detail information see how thread_zone is created and what the
sched_sizeof_thread() function returns for each scheduler.


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