Correct way to call execve?
marcolz at stack.nl
Tue Jul 22 04:54:39 PDT 2003
On Mon, Jul 21, 2003 at 11:24:43AM -0700, Tim Kientzle wrote:
> Chad David wrote:
> >I assumed it was obvious that you could copy the data, but I believe
> >the intent of the original question was to find an alternative. As
> >far as I know there isn't one. A const is a const, except in C++.
> Yes, the intent was to find a way to avoid copying the data.
> I was hoping that someone knew a standard way to
> say "yes, I really do mean to cast away that const,"
> akin to C++ const_cast.
> As far as I can tell, the POSIX-mandated declaration
> of execvp is simply wrong. (SUSv3 even has a comment
> that essentially admits this fact and then vainly tries
> to rationalize it. <sigh>)
I mailed this a long time ago:
const char *cfoo = "bar";
/* From http://www.eskimo.com/~scs/C-faq/q11.10.html:
* References: ANSI Sec. 18.104.22.168, Sec. 22.214.171.124, Sec. 3.5.3
* ISO Sec. 126.96.36.199, Sec. 188.8.131.52, Sec. 6.5.3
* H&S Sec. 7.9.1 pp. 221-2
* Use -Wcast-qual with gcc.
* gcc 184.108.40.206 ok, gcc 2.95.2 not ok.
foo = *((char *const *) &cfoo);
But that doesn't work after 2.7.2
What does work, except with 2.95 is this:
foo = *((char **)((void *)&cfoo)));
Then again: you can always use the union trick:
const void *constant;
hack.constant = cfoo;
foo = hack.nonconst;
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