Understanding GEOM Ranking System

Loren M. Lang lorenl at alzatex.com
Wed Feb 9 16:43:08 PST 2005


I'm slightly confused on the ranking system use in GEOM as described in
the geom(4) manpage.  The wording of the description seems a little
confusing, but the way I understand it is that any geom instance which
has no consumers attached to anything like a disk or acd geom has a rank
of 1.  Any geom that does have some of it's consumers attached to a
provider has a rank of the highest ranked geom providing a service to
this geom.  For example, a ufs filesystem is running on a raid1
configuration between partition d on slice 1 on disk ad0 mirrored with
slice 2 on disk ad1 (no disklabel on second disk).  This makes two disk
geoms for ad0 and ad1 both with rank 1.  Each disk geom has a mbr geom
on top of them with rank 2 (max(1)+1).  The bsd geom on slice 1 of disk
ad0 has rank 3 (max(2)+1).  The mirror geom on top of the bsd geom and
the mbr geom on disk ad1 has a rank of 4 since max(2, 3)+1 = 4.  Then a
dev geom on top of the mirror geom has a rank of 5 (max(4)+1).  That dev
geom is what is mounted as a filesystem on freebsd.  Is this correct?

dev(5) ---> mirror(4) ---> bsd(3) ---> mbr(2) ---> dev(1) ---> ad0
                       \-------------> mbr(2) ---> dev(1) ---> ad1

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