Jemalloc SEGV for 1MB chunk
Rink Springer
rink at FreeBSD.org
Wed Jan 28 04:12:38 PST 2009
Hi,
On Wed, Jan 28, 2009 at 05:31:43PM +0530, Channa wrote:
> size_t size = 1048576 ;
>
> buf = malloc(size);
> for (i = 0; i <= 1048575; i++)
> buf[i] = 'a';
> buf[size]='\0';
> printf("The length of buff is : %d\n",strlen(buf));
> free(buf);
> return 0;
> }
>
> I NULL terminated the string
> buf[size] = '\0' <== The last character is NULL
>
> But still i get a SEGV at strlen.
>
> Could you please tell me if my changes above are correct?
They are not - because size = 1048576, you will get a buffer of 1048576
bytes, that is, buf[0] ... buf[1048575] = buf[0] .. buf[size - 1]. Thus,
you need to do:
buf[size - 1] = '\0';
And it'll work.
Regards,
--
Rink P.W. Springer - http://rink.nu
"Chance favours the prepared mind"
- Penn
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