Performance of SheevaPlug on 8-stable
Mark Tinguely
tinguely at casselton.net
Mon Mar 8 13:57:58 UTC 2010
> On Mon, Mar 08, 2010 at 10:07:14AM +0100, Hans Petter Selasky wrote:
> > On Monday 08 March 2010 09:25:59 Jacques Fourie wrote:
> > > On Mon, Mar 8, 2010 at 5:00 AM, Mark Tinguely <tinguely at casselton.net>
> > wrote:
> > > > <deletes>
> > > >
> > > >> It is still puzzling me why it is not near 80 seconds.
> > > >> This would mean it is loosing something about 5-6 cycles.
> > > >> Well - Ok - the pipeline might be that long and real loops are
> > > >> mostly some instructions longer.
> > > >> But I would still be interested to see Linux results on RM9200.
> > > >>
> > > >> --
> > > >> B.Walter <bernd at bwct.de> http://www.bwct.de
> > > >> Modbus/TCP Ethernet I/O Baugruppen, ARM basierte FreeBSD Rechner uvm.
> > > >
> > > > Thinking way out of the box ... has anyone tried this in single user
> > > > mode?
> > > >
> >
> > Was the output from "vmstat -i" and "top" posted?
>
> No, but I can say that my current and 8.0-current system had almost no
> load.
> My 7.0-current system had about 60-70% load and was about 3 times slower
> than the 8.0 and the patched 9.0 system, so it makes sense.
> Do you expect anything special to see?
>
> --
> B.Walter <bernd at bwct.de> http://www.bwct.de
> Modbus/TCP Ethernet I/O Baugruppen, ARM basierte FreeBSD Rechner uvm.
>
The process is in a tight CPU bound loop. I am thinking that there is
still the interrupt handler (short assembly), find the next interrupt routine
(typically a bitmap shift loop), clock interrupt handler, scheduler,
cpu_switch() (even if it is just to the same process) that goes off every
1/HZ seconds. I would think that if there is an inefficiency in the above
loop, the times should be the same magnitude in single-user as in multi-using.
If you cannot go to single user then the 'vmstat -i' and 'top' is a good
idea - make sure something else is not causing a context switch which would
flush our caches.
The performance counter idea is a good one too.
Wildly grasping, here:
I suppose you could run the program with time and use the wall clock
or "date; a.out; date" to eliminate some problem in the "time" command.
--Mark.
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